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In the figure above (not to scale), ABCD...


In the figure above (not to scale), ABCDE is symmetrical about AF. If `/_C =90^(@)` and `/_ BAF =45^(@)`, then find the `/_E`.

A

`90^(@)`

B

`105^(@)`

C

`135^(@)`

D

Cannot say

Text Solution

Verified by Experts

The correct Answer is:
c
Given, ABCDE is symmetrical about AF.
`:. /_ C = /_D , /_B = /_ E ` and `/_ BAF = /_ EAF`
`:. /_D =90^(@) ` `( :' /_C = 90^(@) )`
`/_EAF =45^(@) ` ` ( :' BAF =45^(@))`
We know that `/_ A + /_B + /_ C + /_ D + /_ E =540^(@)`
`(45^(@)+45^(@))+ /_ B + 90^(@) + 90^(@) + /_ E =540^(@)`
`implies /_B + /_ E =270^(@)` ,brgt `implies /_ B = /_ E =135^(@) ` ` ( :' /_ B = /_ E )`
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