there are exactly two points on the ellipse `x^2/(a^2)+y^2/(b^2)=1` whose distance from its centre is same and equal to `(1/sqrt2)(sqrt(a^2+2b^2))`. The eccentricity of the ellipse is

there are exactly two points on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 whose distance from its centre is same and equal to ((1)/(sqrt(2)))(sqrt(a^(2)+2b^(2))) The eccentricity of the ellipse is

There are exactly two points on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1, whose distance from its centre is same and equal to sqrt((a^(2)+2b^(2))/(2)) .The eccentricity of the ellipse is: (A) (1)/(2)(B)(1)/(sqrt(2)) (C) (sqrt(2))/(3)(D)(sqrt(3))/(2)

There are exactly two points on the ellipse (x^2)/(a^2)+(y^2)/(b^2) =1 whose distance from the centre of the ellipse are equal to sqrt((3a^2-b^2)/(3)) . Eccentricity of this ellipse is

Let there are exactly two points on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 whose distance from (0, 0) are equal to sqrt((a^(2))/(2)+b^(2)) . Then, the eccentricity of the ellipse is equal to

The ecentric angle of the points on the ellipse (x^(2))/(6)+(y^(2))/(2)=1 whose distane from its centre is 2 is/are.

Number of points on the ellipse x^2/25+y^2/7=1 whose distance from the centre of the ellipse is 2sqrt7 is

Find the eccentric angle of a point on the ellipse (x^(2))/(6)+(y^(2))/(2)=1 whose distance from the center of the ellipse is sqrt(5)

The eccentric angle of a point on the ellipse x^(2)/6 + y^(2)/2 = 1 whose distance from the centre of the ellipse is 2, is

The ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is such that its has the least area but contains the circel (x-1)^(2)+y^(2)=1 The eccentricity of the ellipse is