Find the equation of the image of the ci...

Find the equation of the image of the circle `x^2+y^2+8x-16+64=0` in the line mirror `x=0.`

Verified by Experts

The correct Answer is:

`x^(2) + y^(2) + 8x - 16y + 64 = 0 `

CONIC SECTIONS
MODERN PUBLICATION|Exercise EXAMPLE|27 Videos
CONIC SECTIONS
MODERN PUBLICATION|Exercise EXERCISE 11 (A) (SHORT ANSWER TYPE QUESTIONS )|2 Videos
COMPLEX NUMBERS
MODERN PUBLICATION|Exercise CHAPTER TEST|12 Videos
INTRODUCTION TO THREE DIMENSIONAL GEOMETRY
MODERN PUBLICATION|Exercise CHAPTER TEST|12 Videos

Similar Questions

Explore conceptually related problems

The equation of the image of the circle x^(2)+y^(2)-6x-4y+12=0 by the mirror x+y-1=0 is

Find the equation of image of the circle (x-1)^2 + (y+2)^2 =5^0 in the x-axis.

The equation of the image of the circle (x-3)^(2)+(y-2)=1 in the mirror x+y=19, is

The equation of the image of the circle x^(2)+y^(2)+16x-24y+183=0 by the line mirror 4x+7y+13=0 is :

The equation of the image ofthe circle x^(2)+y^(2)+16x-24y+183=0 by the line mirror 4x+7y+13=0 is

Find the image of the circle x^(2)+y^(2)-2x+4y-4=0 in the line 2x-3y+5=0

Find the equation of the normals to the circle x^(2)+y^(2)-8x-2y+12=0 at the point whose ordinate is -1

The equation of the image of the lines y=|x| in the line mirror x = 2 is

Find the equation of the normal to the circle x^(2)+y^(2)-2x=0 parallel to the line x+2y=3.