Find the equation of the parabola whose ...

Find the equation of the parabola whose latusreçtum is 4 units, axis is the line 3x + 4y - 4 = 0 and the tangent at the vertex is the line 4x - 3y +7 = 0.

Verified by Experts

The correct Answer is:

`(3x + 4y - 4)^(2) = 20 (4x - 3y + 4)`.

CONIC SECTIONS
MODERN PUBLICATION|Exercise EXAMPLE|27 Videos
CONIC SECTIONS
MODERN PUBLICATION|Exercise EXERCISE 11 (A) (SHORT ANSWER TYPE QUESTIONS )|2 Videos
COMPLEX NUMBERS
MODERN PUBLICATION|Exercise CHAPTER TEST|12 Videos
INTRODUCTION TO THREE DIMENSIONAL GEOMETRY
MODERN PUBLICATION|Exercise CHAPTER TEST|12 Videos

Similar Questions

Explore conceptually related problems

Find the equation of the parabola whose latusretum is 4 units,axis is the line 3x+4y - 4=0 and the tangent at the vertex is the line 4x-3y+7=0

Find the equation of the parabola whose latus- rectum is 4 units,axis is the line 3x+4y-4=0 and the tangent at the vertex is the line 4x-3y+7=0

Find the equation of the parabola whose latus- rectum is 4 units,axis is the line 3x+4y-4=0 and the tangent at the vertex is the line 4x-3+7=0 .

The equation of parabola whose latus rectum is 2 units, axis of line is x+y-2=0 and tangent at the vertex is x-y+4=0 is given by

Find the equation of the parabola whose focus is (5,3) and directrix is the line 3x-4y+1=0.

Find the equation to the parabola whose focus is (5, 3) and directrix the line 3x-4y+1=0 .

Find the equation of the parabola whose vertex is at the origin and directrix is the line y-4=0

Find the equation of the parabola whose focus is the point (0,0) and the directrix is the straight line 3x-4y+2=0

Find the equation of the parabola whose focus is at (0, 0) and vertex is at the intersection of the line x+y=1 and x-y=3 .