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The equation of a circle with origin as ...

The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3 a is

A

`x^(2) + y^(2) = 9a^(2) `

B

`x^(2) + y^(2) = 16a^(2) `

C

`x^(2) + y^(2) = 4a^(2) `

D

`x^(2) + y^(2) = a^(2) `

Text Solution

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The correct Answer is:
C
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The equation of the circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is: a x^(2)+y^(2)=9a^(2) b) x^(2)+y^(2)=16a^(2) c) x^(2)+y^(2)=4a^(2) d) x^(2)+y^(2)=a^(2)

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