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The equation of the chord joining the po...

The equation of the chord joining the points `(x_(1) , y_(1))` and `(x_(2), y_(2))` on the rectangular hyperbola xy = `c^(2)` is :

A

`(x)/(x_(1) + x_(2)) + (y)/(y_(1) + y_(2))` = 1

B

`(x)/(x_(1) - x_(2)) + (y)/(y_(1) - y_(2))` = 1

C

`(x)/(y_(1) + y_(2)) + (y)/(x_(1) + x_(2))` = 1

D

`(x)/(y_(1) - y_(2)) + (y)/(x_(1) - x_(2))` = 1

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To find the equation of the chord joining the points \((x_1, y_1)\) and \((x_2, y_2)\) on the rectangular hyperbola given by \(xy = c^2\), we can follow these steps: ### Step 1: Verify that the points lie on the hyperbola Since the points \((x_1, y_1)\) and \((x_2, y_2)\) lie on the hyperbola \(xy = c^2\), we can write: \[ y_1 = \frac{c^2}{x_1} \quad \text{and} \quad y_2 = \frac{c^2}{x_2} \] ### Step 2: Find the slope of the chord The slope \(m\) of the line joining the two points can be calculated using the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Substituting the values of \(y_1\) and \(y_2\): \[ m = \frac{\frac{c^2}{x_2} - \frac{c^2}{x_1}}{x_2 - x_1} \] To simplify this, we find a common denominator: \[ m = \frac{c^2 \left(\frac{x_1 - x_2}{x_1 x_2}\right)}{x_2 - x_1} = -\frac{c^2 (x_1 - x_2)}{(x_1 x_2)(x_2 - x_1)} = -\frac{c^2}{x_1 x_2} \] ### Step 3: Use the point-slope form to write the equation of the chord Using the point-slope form of the equation of a line, we have: \[ y - y_1 = m(x - x_1) \] Substituting \(m\) and \(y_1\): \[ y - \frac{c^2}{x_1} = -\frac{c^2}{x_1 x_2}(x - x_1) \] ### Step 4: Rearranging the equation Cross-multiplying to eliminate the fraction: \[ x_1 x_2 (y - \frac{c^2}{x_1}) = -c^2 (x - x_1) \] Expanding both sides: \[ x_1 x_2 y - c^2 x_2 = -c^2 x + c^2 x_1 \] Rearranging gives: \[ x_1 x_2 y + c^2 x = c^2 (x_1 + x_2) \] ### Step 5: Final equation Dividing through by \(c^2\): \[ \frac{x_1 x_2 y}{c^2} + \frac{x}{c^2} = \frac{x_1 + x_2}{c^2} \] Thus, the equation of the chord can be written as: \[ \frac{y}{\frac{c^2}{x_1 x_2}} + \frac{x}{c^2} = \frac{1}{\frac{1}{x_1} + \frac{1}{x_2}} \] This simplifies to: \[ \frac{y}{\frac{c^2}{x_1 + x_2}} + \frac{x}{c^2} = 1 \] ### Final Answer The equation of the chord joining the points \((x_1, y_1)\) and \((x_2, y_2)\) on the rectangular hyperbola \(xy = c^2\) is: \[ \frac{y}{\frac{c^2}{x_1 + x_2}} + \frac{x}{c^2} = 1 \]
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MODERN PUBLICATION-CONIC SECTIONS -OBJECTIVE TYPE QUESTIONS (MULTIPLE CHOICE QUESTIONS )
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  2. If the distance between the foci of a hyperbola is 16 and its eccen...

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  3. The length of the transverse axis of a hyperbola is 7 and it passes th...

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  4. Equation of the hyperbola with eccentricity 3/2 and foci at (±2,0) is

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  5. The equation of the chord joining the points (x(1) , y(1)) and (x(2), ...

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  6. The foci of the hyperbola (x^(2))/(16) -(y^(2))/(9) = 1 is :

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  7. Centre of the circle 2x^(2) + 2y^(2) -x = 0 is :

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  8. For the circle x^(2) + y^(2) = 25, the point (-2.5, 3.5) lies :

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  9. (i) Centre of the circle x^(2) + y^(2) - 8x + 10 y + 12 = 0 is Cen...

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  10. Length of the semi-latus -rectum of parabola : x^(2) = -16y is :

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  11. The focus of the parabola y^(2) = - 4ax is :

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  12. The length of latus-rectum of parabola x^(2) = - 16 y is :

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  13. The eccentricity of the ellipse (x^(2))/(a^(2)) +(y^(2))/(b^(2)) = 1 ...

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  14. If the slope of the line containg the point (2,5) and (x, - 4) is 3, t...

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  15. If the slope of a line is not defined then the line :

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  16. Eccentricity of the hyperbola x^(2) - y^(2) = a^(2) is :

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  17. The foci of the ellipse (x^(2))/(4) +(y^(2))/(25) = 1 are :

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  18. The co-ordinates of the foci of the ellipse 9x^(2) + 4y^(2) = 36 are ...

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  19. If e and e' be the eccentricities of two conics S=0 and S'=0 and if e^...

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  20. The equatio (x ^(2 ))/( 2 -r) + (y ^(2))/(r -5) +1=0 represents an ell...

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