Prove that the product of the lengths of the perpendiculars drawn from the points `(sqrt(a^2-b^2),0)`and `(-sqrt(a^2-b^2),0)`to the line `x/a``costheta``+``y/b``sintheta=1`is `b^2`.

Prove that the product of the length of the perpendiculars from the points (sqrt(a^2 -b^2) , 0) and (-sqrt(a^2 -b^2), 0) to the line x/a cos theta + y/a cos theta + y/b sin theta = 1 is

23, Prove that the product of the lengths of the perpendiculars drawn from thepoints (a?-B,0) and (-Va -B,0) to the line cos 0 sin 6 =lis B.

The product of the length of the perpendiculars drawn from the point (1,1) to the pair of lines x^(2)+xy-6y^(2)=0

Show that the product of the perpendiculars from the points (+-sqrt(a^(2)-b^(2)),0) to the line (x)/(a)cos theta+(y)/(b)sun theta=1 is equal to b^(2)

The product of the perpendiculars drawn from (2,-1) to the pair of lines x^(2)-3xy+2y^(2)=0 is

The product of the perpendiculars drawn from the point (1,2) to the pair of lines x^(2)+4xy+y^(2)=0 is

What is the product of the perpendiculars from the two points (pm sqrt(b^(2)-a^(2)), 0) to the line ax cos phi + by sin phi =ab ?