If p is the length of perpendicular from the origin on the line `(x)/(a)+(y)/(b)=1` and `a^(2)`,`p^(2)` and `b^(2)` are in AP, the show that `a^(4)+b^(4)=0`.

The length of perpendicular from the origin on the line x/a + y/b = 1 is -

If 2p is the length of perpendicular from the origin to the lines (x)/(a)+(y)/(b)=1, then a^(2),8p^(2),b^(2) are in

I.If p is the length of the perpendicular from the origin on the line (x)/(a)+(y)/(b)=1 and a^(2),p^(2),b^(2) are in A.P,then a^(4)-2p^(2)a^(2)+2p^(4)=

Find the length of the perpendicular from the origin to the line 4x+3y-2=0

If p is the length of the perpendicular drawnfrom the origin upon the line (x)/(a)+(y)/(b)=1 and a^(2),p^(2),b^(2) are in arithmetic progression,) then |ab| is equal to

Find the length of perpendicular from origin to the line x+7y+4sqrt(2)=0 .

If p is the length of the perpendicular from the origin to the line (x)/(a) + (y)/(b) = 1 , then which of the following is ture ?