Show that the area of the triangle formed by the straight lines ` y = m_(1) x + c_(1) `, ` y = m_(2) x + c_(2) ` and x = 0 is `(1)/(2)(c_(1)-c_(2))^(2)/(|m_(1)-m_(2)|)` sq . Units .

Show that the area of the triangle formed by the lines y=m_(1)x+c_(1),y=m_(2)x+c_(2) and and is 2|m_(1)-m_(2)|

The area of the triangle formed by the lines y=m_(1x)+c_(1),y=m_(2),x+c_(2) and x=0 is (1)/(2)((c_(1)+c_(2))^(2))/(|m_(1)-m_(2)|) b.(1)/(2)((c_(1)-c_(2))^(2))/(|m_(1)+m_(2)|) c.(1)/(2)((c_(1)-c_(2))^(2))/(|m_(1)-m_(2)|) d.((c_(1)-c_(2))^(2))/(|m_(1)-m_(2)|)

Find the coordinates that the straight lines y=m_(1)x+c_(1),y=m_(2)x+c_(2) and y=m_(2)x+c_(3) may meet in a point.

Show that the area of the triangle formed buy the lines y=m_(1)x,y=m_(2)x and y=c is equlto (c^(2))/(4)(sqrt(33)+sqrt(11)) where m_(1),m_(2) are the roots of the equation xy^(2)=(sqrt(3)+2)x+sqrt(3)-1=0

If m_1 and m_2 are the roots of the equation x^2-a x-a-1=0 , then the area of the triangle formed by the three straight lines y=m_1x ,y=m_2x , and y=a(a!=-1) is (a^2(a+2))/(2(a+1))ifa >-1 (-a^2(a+2))/(2(a+1))ifa >-1 (-a^2(a+2))/(2(a+1))if-2

If m_(1) and m_(2) are the roots of the equation x^(2)-ax-a-1=0 then the area of the triangle formed by the three straight lines y=m_(1)xy=m_(2)x and y=a is

The area of the region bounded by the straight lines x=2y, x=3y and x=6 , is (A) 3 sq.units (B) 4 sq.units (C) 2 sq.units (D) 1 sq.unit