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If A={0,1,3}, then the number of relatio...

If `A={0,1,3}`, then the number of relations on A is____________.

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To find the number of relations on the set \( A = \{0, 1, 3\} \), we can follow these steps: ### Step 1: Understand the Concept of Relations A relation on a set \( A \) is a subset of the Cartesian product \( A \times A \). The Cartesian product \( A \times A \) consists of all possible ordered pairs where the first element is from set \( A \) and the second element is also from set \( A \). ### Step 2: Determine the Size of the Set The set \( A \) has 3 elements: \( 0, 1, \) and \( 3 \). ### Step 3: Calculate the Cartesian Product The Cartesian product \( A \times A \) will have \( n^2 \) pairs, where \( n \) is the number of elements in set \( A \). Since \( A \) has 3 elements, we calculate: \[ |A \times A| = 3 \times 3 = 9 \] Thus, the set \( A \times A \) consists of the following pairs: \[ A \times A = \{(0,0), (0,1), (0,3), (1,0), (1,1), (1,3), (3,0), (3,1), (3,3)\} \] ### Step 4: Determine the Number of Subsets A relation is any subset of \( A \times A \). The number of subsets of a set with \( m \) elements is given by \( 2^m \). Since \( A \times A \) has 9 elements, the number of subsets (relations) is: \[ \text{Number of relations} = 2^{|A \times A|} = 2^9 \] ### Step 5: Calculate the Final Answer Calculating \( 2^9 \): \[ 2^9 = 512 \] Thus, the number of relations on the set \( A \) is \( 512 \). ### Final Answer The number of relations on \( A \) is **512**. ---
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