If f (x) = sin x, g(x) = `x^(2)`, if `x inR`, then find [(fog)(x)].

Answer

To find \((f \circ g)(x)\), we need to evaluate the composition of the functions \(f\) and \(g\). Here are the steps to solve the problem:

### Step-by-Step Solution:

1. **Identify the Functions**:
- We have \(f(x) = \sin x\) and \(g(x) = x^2\).

2. **Write the Composition**:
- The composition of the functions \(f\) and \(g\) is written as \((f \circ g)(x) = f(g(x))\).

3. **Substitute \(g(x)\) into \(f\)**:
- We know that \(g(x) = x^2\). Now we substitute \(g(x)\) into \(f\):
\[ f(g(x)) = f(x^2) \]

4. **Evaluate \(f(x^2)\)**:
- Now we need to find \(f(x^2)\). Since \(f(x) = \sin x\), we replace \(x\) with \(x^2\):
\[ f(x^2) = \sin(x^2) \]

5. **Final Result**:
- Thus, the result of \((f \circ g)(x)\) is:
\[ (f \circ g)(x) = \sin(x^2) \]

### Final Answer:
\[ (f \circ g)(x) = \sin(x^2) \]