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If the mappings f and g are given by : f...

If the mappings f and g are given by : `f={(1,2),(3,5),(4,1)} and g={(2,3),(5,1),(1,3)}`, write fog.

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To find the composition of the functions \( f \) and \( g \), denoted as \( f \circ g \), we need to follow these steps: ### Step 1: Understand the Functions We have two mappings: - \( f = \{(1, 2), (3, 5), (4, 1)\} \) - \( g = \{(2, 3), (5, 1), (1, 3)\} \) ### Step 2: Determine the Output of \( g \) To find \( f \circ g \), we need to find the output of \( g \) for each input in the domain of \( g \) and then use that output as the input for \( f \). #### 2.1: Calculate \( g(2) \) From the mapping \( g \): - \( g(2) = 3 \) #### 2.2: Calculate \( g(5) \) From the mapping \( g \): - \( g(5) = 1 \) #### 2.3: Calculate \( g(1) \) From the mapping \( g \): - \( g(1) = 3 \) ### Step 3: Find \( f(g(x)) \) Now we will use the outputs from \( g \) to find the corresponding outputs from \( f \). #### 3.1: Calculate \( f(g(2)) = f(3) \) From the mapping \( f \): - \( f(3) = 5 \) #### 3.2: Calculate \( f(g(5)) = f(1) \) From the mapping \( f \): - \( f(1) = 2 \) #### 3.3: Calculate \( f(g(1)) = f(3) \) From the mapping \( f \): - \( f(3) = 5 \) ### Step 4: Compile the Results Now we can compile the results of \( f \circ g \): - \( f(g(2)) = 5 \) gives us the pair \( (2, 5) \) - \( f(g(5)) = 2 \) gives us the pair \( (5, 2) \) - \( f(g(1)) = 5 \) gives us the pair \( (1, 5) \) ### Final Result Thus, the composition \( f \circ g \) is: \[ f \circ g = \{(2, 5), (5, 2), (1, 5)\} \]
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