Home
Class 12
MATHS
Are f and g both necessarily onto, if go...

Are f and g both necessarily onto, if `gof`is onto?

Text Solution

Verified by Experts

The correct Answer is:
f is not onto
Promotional Banner

Topper's Solved these Questions

  • RELATIONS AND FUNCTIONS

    MODERN PUBLICATION|Exercise COMPETITION FILE (Questions from JEE Main)|7 Videos

  • PROBABILITY

    MODERN PUBLICATION|Exercise MOCK TEST SECTION D|6 Videos

  • THREE DIMENSIONAL GEOMETRY

    MODERN PUBLICATION|Exercise CHAPTER TEST 11|11 Videos

Similar Questions

Explore conceptually related problems

Consider functions f and g such that composite gof is defined and is one-one.Are f and g both necessarily one-one.

Let f:A rarr B and g:B rarr C be two functions.Then; if gof is onto then g is onto; if gof is one one then f is one-one and if gof is onto and g is one one then f is onto and if gof is one one and f is onto then g is one one.

Show that if f:A rarr B and are onto,then are onto,then is also onto.

Let f: R->R be any function. Also g: R->R is defined by g(x)=|f(x)| for all xdot Then is a. Onto if f is onto b. One-one if f is one-one c. Continuous if f is continuous d. None of these

If f:A rarr B and g:B rarr C are onto functions show that gof is an onto function.

A function is said to be bijective if it is both one-one and onto, Consider the mapping f : A rarr B be defined by f(x) = (x-1)/(x-2) such that f is a bijection. Let g : R - {2} rarr R - {1} be defined by g(x) = 2f(x) - 1 . Then g(x) in terms of x is :

A function is said to be bijective if it is both one-one and onto, Consider the mapping f : A rarr B be defined by f(x) = (x-1)/(x-2) such that f is a bijection. Domain of f is

A function is said to be bijective if it is both one-one and onto, Consider the mapping f : A rarr B be defined by f(x) = (x-1)/(x-2) such that f is a bijection. Range of f is :

A function is said to be bijective if it is both one-one and onto, Consider the mapping f : A rarr B be defined by f(x) = (x-1)/(x-2) such that f is a bijection. A function f(x) is said to be one-one iff :