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Solve the following system of equatio...

Solve the following system of equations by matrix method : `x+y-2=3` `2x+3y+z=10` `3x-y-7z=1` `x+y+z=3` `2x-y+z=-1` `2x+y-3z=-9` `6x-12 y+25 z=4` `4x+15 y-20 z=3` `2x+18 y+15 z=10` `3x+4y+7z=14` `2x-y+3z=4` `x+2y-3z=0` `2/x-3/y+3/z=10` `1/x+1/y+1/z=10` `3/x-1/y+2/z=13` `5x+3y+z=16` `2x+y+3z=19` `x+2y+4z=25` `3x+4y+2z=8` `2y-3z=3` `x-2y+6z=-2` `2x+y+z=2` `x+3y-z=5` `3x+y-2z=6` `2x+6y=2` `3x-z=-8` `2x-y+z=-3` `2y-z=1` `x-y+z=2` `2x-y=0` `8x+4y+3z=18` `2x+y+z=5` `x+2y+z=5` `x+y+z=6` `x+2z=7` `3x+y+z=12` `2/x+3/y+(10)/z=4,` `4/x-6/y+5/z=1` `6/x+9/y-(20)/z=2; x , y , z!=0` `x-y+2z=7` `3x+4y-5z=-5` `2x-y+3z=12`

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The correct Answer is:
`x=(1)/(2)`, `y=(1)/(3)`, `z=(1)/(5)`
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