Find the inverse of the `matrix A= [(1,b),(c,(1+bc)/a]` and show that `aA^(-1)=(a^2+b c+1)I-a A`

Find the inverse of the matrix A=[abc(1+bc)/(a)] and show that aA^(-1)=(a^(2)+bc+1)I-aA

Find the inverse of matrix [{:(1," "2),(2,-1):}]

" The inverse of the matrix "([1,0,0],[a,1,0],[b,c,1])" is "

Using elementary transformation, find the inverse of the matrix A=[(a,b),(c,((1+bc)/a))] .

For the matrix A=[{:(,3,2),(,1,1):}] Find a & b so that A^(2)+aA+bI=0 . Hence find A^(-1)

Find the value of det[[1,a,a^(2)-bc1,b,b^(2)-ac1,c,c^(2)-ab]]

If a, b and c are any three vectors and their inverse are a^(-1), b^(-1) and c^(-1) and [a b c]ne0 , then [a^(-1) b^(-1) c^(-1)] will be

If the matrix {:[(a,b),(c,d)]:} is commutative with matrix {:[(1,1),(0,1)]:} , then

Consider a matrix A=[(0,1,2),(0,-3,0),(1,1,1)]. If 6A^(-1)=aA^(2)+bA+cI , where a, b, c in and I is an identity matrix, then a+2b+3c is equal to

For the matrix A=[{:(2,1),(3,0):}] , find the numbers 'a' and 'b' such that A^(2)+aA+bI=O . Hence , find A^(-1) .