If a triangle ABC, inscribed in a fixed circle, be slightly varied in such away as to have its vertices always on the circle, then show that `(d a)/(c a sA)+(d b)/(cosB)+(d c)/(cosC)=0.`

If a triangle ABC ,inscribed in a fixed circle,be slightly varied in such away as to have its vertices always on the circle,then show that (da)/(cas A)+(db)/(cos B)+(dc)/(cos C)=0

If a circle is inscribed in right angled triangle ABC with right angle at B, show that the diameter of the circle is equal to AB+BC-AC.

A variable triangle A B C is circumscribed about a fixed circle of unit radius. Side B C always touches the circle at D and has fixed direction. If B and C vary in such a way that (BD) (CD)=2, then locus of vertex A will be a straight line. parallel to side BC perpendicular to side BC making an angle (pi/6) with BC making an angle sin^(-1)(2/3) with B C

A variable triangle ABC is circumscribed about a fixed circle of unit radius. Side BC always touches the circle at D and has fixed direction. If B and C vary in such a way that (BD). (CD)=2, then locus of vertex A will be a straight line

If A is the area and C is the circumference of a circle,then its radius is (A)/(C)( b) (2A)/(C)(3A)/(C) (d) (4A)/(C)

If in a triangle, the area is numerically equal to the perimeter, then the radius of the inscribed circle of the triangle is (a) 1 (b) 1.5 (c) 2 (d) 3

An equilateral triangle ABC is inscribed in a circle of radius 20 sqrt3 cm The centroid of the triangle ABC is at a distance d from the vertex A. What is d equal to?

If in a triangle ABC, (cosA)/a=(cosB)/b=(cosC)/c ,then the triangle is

Let aandb represent the lengths of a right triangles legs.If d is the diameter of a circle inscribed into the triangle,and D is the diameter of a circle circumscribed on the triangle,the d+D equals.(a)a + b (b) 2(a+b)(c)(1)/(2)(a+b)( d) sqrt(a^(2)+b^(2))

In a triangle ABC, the side a,b,c are such that they are the roots of then (cosA)/a+(cosB)/b+(cosC)/c=