`int(dx)/(1+3sin^2x).`

int(dx)/(1+sin^2x)=

int(dx)/(1+3sin^(2)x)

Evaluate : int(dx)/(1-sin^2x)

Evaluate : (i) int(dx)/((1+3sin^(2)x)) (ii) int(dx)/((3+2cos^(2)x))

Let I=int(dx)/(1+3sin^(2)x)=(1)/(2)tan^(-1)(2f(x))+C (where, C is the constant of integration). If f((pi)/(4))=1 , then the fundamental period of y=f(x) is

int (sin 2x)/(1+sin^2x)dx=

int(1)/(1+3 sin ^(2)x)dx is equal to

int(sin2x)/(1+sin^(2)x)dx=

Evaluate int(1)/(3-2sin^(2)x)dx