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v31

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The correct Answer is:
`x e^x-e^x+c`
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Find the square root of the following decimal numbers.(i) 2.56 (ii) 7.29 (iii) 51.84 (iv) 42.25(v) 31.36

The square root of the complex number z= (u^(2))/(v^(2))+(v^(2))/(u^(2))+(1)/(2i)((u)/(v)+(v)/(u))+(31)/(16) is (in terms of u, v, w )

Knowledge Check

  • The reduction potential of the two half cell reaction (occurring in an electrochemical cell) are PbSO_(4)(s)+2e^(-)rarrPb(s)+SO_(4)^(2-)(aq)(E^(@)=-0.31V) Ag^(+)(aq)+e^(-)rarrAg(s)(E^(@)=0.80V) The feasible reaction will be

    A
    `Pb(s)+SO_(4)^(2-)(aq)+2Ag^(+)+(aq)rarr2Ag(s)+PbSO_(4)(s)`
    B
    `PbSO_(4)(s)+2Ag^(+)(aq)rarrPb(s)+SO_(4)^(2-)(aq)+2Ag(s)`
    C
    `Pb(s)+SO_(4)^(2-)(s)+Ag(s)rarrAg^(+)(aq)+PbSO_(4)(s)`
    D
    `PbSO_(4)(s)+Ag(s)rarrAg^(+)(aq)+Pb(s)+SO_(4)^(2-)(aq)`

  • The reduction potential of the two half cell reactions (occuring in an electrochemical cell) are PbSO_(4)+ 2e^(-)rarrPb+SO_(4)^(2-) (E^(@)=-0.31V) Ag^(+)(aq)+e^(-)rarrAg(s)(E^(@)=+0.80V) The fessible reaction will be

    A
    `Pb+SO_(4)^(2-)+2Ag^(+)(aq)rarr2Ag(s)+PbSO_(4)`
    B
    `PbSO_(4)+2Ag^(+)(aq)rarrPb+SO_(4-)^(2)+2Ag(s)`
    C
    `Pb+SO_(4)^(2-)+Ag(s)rarrAg^(+)(aq)+PbSO_(4)^(2-)`
    D
    `PbSO_(4)+Ag(S)rarrAg^(+)(aq)+Pb+SO_(4)^(2-)`

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