int0^(pi) sin3x dx=2/3...

`int_0^(pi) sin3x dx=2/3`

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int_(0)^(pi) sin 3x dx

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Knowledge Check

int_(0)^(pi) [2sin x]dx=

A

`2pi//3`

B

`-5pi//3`

C

`-pi`

D

`-2pi`

What is int_0^(pi//2) (sin^3 x)/(sin^3x+cos^3x) dx

A

`pi`

B

`pi/2`

C

`pi/4`

D

0

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IF int_0^a sqrtx dx=2a int_0^(pi//2) sin^3 x dx, find int_a^(a+1) x dx .

Evaluate the following : int_(0)^(pi)x sin^(3)x dx

int_(0)^(pi) x f(sin x)dx= (pi)/(2) int_(0)^(pi) f(sin x)dx = pi int_(0)^(pi//2) f (sin x)dx

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