intx/((1+sinx))dx...

`intx/((1+sinx))dx`

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The correct Answer is:

`- x tan`

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MODERN PUBLICATION-INTEGRALS-REVISION EXERCISE

int(2sin2theta-costheta)/(6-cos^2theta-4sintheta) d theta
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int x^8/(1+x^3)^(1//3)dx
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intx/((1+sinx))dx
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inte^x((1-x)/(1+x^2))^2dx
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int(tan theta d theta)/(1-sintheta)
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int (x^2-2)/sqrt(3-x^2) dx
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intdx/(sin^3xcos^5x)
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Evaluate: intsqrt((a+x)/x)\ dx
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int(0)^(pi//2)(sqrt(tanx)+sqrt(cotx))dx
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int0^pi sqrt(1+cosx)/(1-cosx)^(5//2) dx
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int cos (2 cot^-1 sqrt((1-x)/(1+x)))dx
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Evaluate: int(logx)/((x+1)^2)\ dx
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int(sqrt(cosx))/(sinx)dx
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(i) int 1/ (cos^4x+sin^4x)dx (ii) int 1/(sin^4x+sin^2x cos^2x+cos^4x...
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int (sin^-1sqrtx-cos^-1 sqrtx)/(sin^-1 sqrtx+ cos^-1 sqrtx)
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Evaluate: int(sqrt(cos2x))/(sinx)dx
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Evaluate: int0^pi(e^(cosx))/(e^(cosx)+e^(-cosx))dx
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int2^5 (x^2+x)dx
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int(0)^(2) xsqrt(2-x)dx
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int(0)^(2pi)|cosx|dx=4
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