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MODERN PUBLICATION-INTEGRALS-REVISION EXERCISE
- Evaluate: intsqrt((a+x)/x)\ dx
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- int(0)^(pi//2)(sqrt(tanx)+sqrt(cotx))dx
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- int0^pi sqrt(1+cosx)/(1-cosx)^(5//2) dx
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- int cos (2 cot^-1 sqrt((1-x)/(1+x)))dx
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- Evaluate: int(logx)/((x+1)^2)\ dx
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- int(sqrt(cosx))/(sinx)dx
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- (i) int 1/ (cos^4x+sin^4x)dx (ii) int 1/(sin^4x+sin^2x cos^2x+cos^4x...
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- int (sin^-1sqrtx-cos^-1 sqrtx)/(sin^-1 sqrtx+ cos^-1 sqrtx)
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- Evaluate: int(sqrt(cos2x))/(sinx)dx
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- Evaluate: int0^pi(e^(cosx))/(e^(cosx)+e^(-cosx))dx
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- int2^5 (x^2+x)dx
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- int(0)^(2) xsqrt(2-x)dx
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- int(0)^(2pi)|cosx|dx=4
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- int(0)^(pi//2)log(tanx+cotx)dx=pi(log2)
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- Prove that int0^(pi//2) (sinx cos x)/(a^2 sin^2 x+b^2 cos^2x) dx=1/(...
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- Evaluate: int0^(pi//2)sqrt(costheta)sin^3thetadtheta
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- int(0)^(pi//4)(sqrt(tanx)+sqrt(cotx))dx equals
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- Evaluate: int0^1 1/(sqrt(1+x)-sqrtx) dx
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- Evaluate: int0^(pi/2) (sin2x tan^(-1)(sinx))dx
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- Evaluate: int0^(pi//2)(cos^2x)/(cos^2x+4sin^2x)dx
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