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Find the position vector of R, which div...

Find the position vector of R, which divides the line joining two points `P(2vec(a)+vec(b))` and `Q(vec(a)-3vec(b))` externally in the ratio 1 : 2. Also show that P is the middle point of the segment RQ.

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To solve the problem, we need to find the position vector of point R, which divides the line segment joining points P and Q externally in the ratio 1:2. We also need to show that point P is the midpoint of segment RQ. ### Step 1: Identify the position vectors of points P and Q. Given: - \( P = 2\vec{a} + \vec{b} \) - \( Q = \vec{a} - 3\vec{b} \) ### Step 2: Use the external division formula. The formula for the position vector \( \vec{R} \) that divides the line joining points \( P \) and \( Q \) externally in the ratio \( m:n \) is given by: \[ \vec{R} = \frac{m\vec{P} - n\vec{Q}}{m - n} \] Here, \( m = 2 \) and \( n = 1 \). ### Step 3: Substitute the values into the formula. Substituting \( \vec{P} \) and \( \vec{Q} \) into the formula: \[ \vec{R} = \frac{2(2\vec{a} + \vec{b}) - 1(\vec{a} - 3\vec{b})}{2 - 1} \] ### Step 4: Simplify the expression. Calculating the numerator: \[ = \frac{(4\vec{a} + 2\vec{b}) - (\vec{a} - 3\vec{b})}{1} \] \[ = 4\vec{a} + 2\vec{b} - \vec{a} + 3\vec{b} \] \[ = (4\vec{a} - \vec{a}) + (2\vec{b} + 3\vec{b}) \] \[ = 3\vec{a} + 5\vec{b} \] Thus, the position vector of \( R \) is: \[ \vec{R} = 3\vec{a} + 5\vec{b} \] ### Step 5: Show that P is the midpoint of segment RQ. To find the midpoint of segment RQ, we use the midpoint formula: \[ \text{Midpoint} = \frac{\vec{R} + \vec{Q}}{2} \] Substituting \( \vec{R} \) and \( \vec{Q} \): \[ = \frac{(3\vec{a} + 5\vec{b}) + (\vec{a} - 3\vec{b})}{2} \] Calculating the numerator: \[ = \frac{(3\vec{a} + \vec{a}) + (5\vec{b} - 3\vec{b})}{2} \] \[ = \frac{4\vec{a} + 2\vec{b}}{2} \] \[ = 2\vec{a} + \vec{b} \] Since \( \vec{P} = 2\vec{a} + \vec{b} \), we conclude that: \[ \text{Midpoint of RQ} = \vec{P} \] ### Final Conclusion: Thus, the position vector of \( R \) is \( 3\vec{a} + 5\vec{b} \) and point \( P \) is indeed the midpoint of segment \( RQ \). ---
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