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Prove that : (vec(b)+vec(c )).{(vec(...

Prove that :
`(vec(b)+vec(c )).{(vec(c )+vec(a))xx(vec(a)+vec(b))}=2 [vec(a)vec(b)vec(c )]`.

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If vec(a).vec(b)xx vec(c ) ≠ 0 and vec(a')=(vec(b)xx vec(c ))/(vec(a).vec(b)xx vec(c )), vec(b')=(vec(c )xx vec(a))/(vec(a).vec(b)xx vec(c )), vec(c')=(vec(a)xx vec(b))/(vec(a).vec(b)xx vec(c )) , show that : vec(a').(vec(b')xx vec(c'))=(1)/(vec(a).(vec(b)xx vec(c )))

If vec(a).vec(b)xx vec(c )≠0 and vec(a')=(vec(b)xx vec(c ))/(vec(a).vec(b)xx vec(c )), vec(b')=(vec(c )xx vec(a))/(vec(a).vec(b)xx vec(c )), vec(c')=(vec(a)xx vec(b))/(vec(a).vec(b)xx vec(c )) , show that : vec(a).vec(a')+vec(b).vec(b')+vec(c ).vec(c')=3

If vec(a).vec(b)xx vec(c ) ≠ 0 and vec(a')=(vec(b)xx vec(c ))/(vec(a).vec(b)xx vec(c )), vec(b')=(vec(c )xx vec(a))/(vec(a).vec(b)xx vec(c )), vec(c')=(vec(a)xx vec(b))/(vec(a).vec(b)xx vec(c )) , show that : vec(a).vec(a')+vec(b). vec(b')+vec(c ). vec(c')=3 .