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Find the vector equation of the line thr...

Find the vector equation of the line through (4,3, -1) and parallel to the line :
`vec(r) = (2 hati - hatj + 3 hatk) + lambda (3 hati - hatj + 4 hatk)`.

A

`vec(r) = (4 hati + 3hatj + hatk) + lambda (3 hati - hatj + 4 hatk)`

B

`vec(r) = (4 hati + 3hatj - hatk) + lambda (3 hati - hatj + 4 hatk)`

C

`vec(r) = (4 hati - 3hatj - hatk) + lambda (3 hati - hatj + 4 hatk)`

D

`vec(r) = (4 hati + 3hatj - hatk) + lambda (3 hati - hatj - 4 hatk)`

Text Solution

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The correct Answer is:
To find the vector equation of the line that passes through the point \( (4, 3, -1) \) and is parallel to the line given by the vector equation: \[ \vec{r} = (2 \hat{i} - \hat{j} + 3 \hat{k}) + \lambda (3 \hat{i} - \hat{j} + 4 \hat{k}), \] we can follow these steps: ### Step 1: Identify the point through which the line passes The line we want to find passes through the point \( (4, 3, -1) \). We can represent this point in vector form as: \[ \vec{A} = 4 \hat{i} + 3 \hat{j} - 1 \hat{k}. \] ### Step 2: Identify the direction vector of the given line From the given line equation, we can extract the direction vector. The direction vector \( \vec{B} \) is the coefficient of \( \lambda \): \[ \vec{B} = 3 \hat{i} - \hat{j} + 4 \hat{k}. \] ### Step 3: Write the vector equation of the required line The vector equation of a line can be written in the form: \[ \vec{r} = \vec{A} + \lambda \vec{B}, \] where \( \vec{A} \) is the position vector of a point on the line and \( \vec{B} \) is the direction vector. Substituting the values we have: \[ \vec{r} = (4 \hat{i} + 3 \hat{j} - 1 \hat{k}) + \lambda (3 \hat{i} - \hat{j} + 4 \hat{k}). \] ### Step 4: Simplify the equation Now we can express the equation more clearly: \[ \vec{r} = (4 + 3\lambda) \hat{i} + (3 - \lambda) \hat{j} + (-1 + 4\lambda) \hat{k}. \] This is the required vector equation of the line. ### Final Answer Thus, the vector equation of the line through the point \( (4, 3, -1) \) and parallel to the given line is: \[ \vec{r} = (4 + 3\lambda) \hat{i} + (3 - \lambda) \hat{j} + (-1 + 4\lambda) \hat{k}. \] ---
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MODERN PUBLICATION-THREE DIMENSIONAL GEOMETRY -EXAMPLE
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