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Find the value of 'lambda' so the lines:...

Find the value of `'lambda'` so the lines:
`(1-x)/(3) = (7y -14)/(lambda) = (z-3)/(2) and (7 - 7x)/(3 lambda) = (y -5)/(1 ) = (6 - z)/(5)`
are at right angles. Also, find whether the lines are ntersecting or not .

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The correct Answer is:
To solve the problem, we need to find the value of \( \lambda \) such that the lines \( L_1 \) and \( L_2 \) are at right angles. We will also check if the lines intersect. ### Step 1: Write the equations of the lines in parametric form For line \( L_1 \): \[ \frac{1-x}{3} = \frac{7y - 14}{\lambda} = \frac{z - 3}{2} \] Let \( t \) be the parameter. Then we can express the coordinates as: \[ x = 1 - 3t, \quad y = 2 + \frac{\lambda}{7}t, \quad z = 3 + 2t \] For line \( L_2 \): \[ \frac{7 - 7x}{3\lambda} = \frac{y - 5}{1} = \frac{6 - z}{5} \] Let \( s \) be the parameter. Then we can express the coordinates as: \[ x = 1 - \frac{3\lambda}{7}s, \quad y = 5 + s, \quad z = 6 - 5s \] ### Step 2: Find the direction ratios of the lines For line \( L_1 \), the direction ratios \( b_1 \) are: \[ b_1 = (-3, \frac{\lambda}{7}, 2) \] For line \( L_2 \), the direction ratios \( b_2 \) are: \[ b_2 = (-3\lambda, 1, -5) \] ### Step 3: Set up the condition for the lines to be perpendicular The lines are perpendicular if the dot product of their direction ratios is zero: \[ b_1 \cdot b_2 = 0 \] Calculating the dot product: \[ (-3)(-3\lambda) + \left(\frac{\lambda}{7}\right)(1) + (2)(-5) = 0 \] This simplifies to: \[ 9\lambda + \frac{\lambda}{7} - 10 = 0 \] To eliminate the fraction, multiply through by 7: \[ 63\lambda + \lambda - 70 = 0 \] Combine like terms: \[ 64\lambda - 70 = 0 \] Solving for \( \lambda \): \[ 64\lambda = 70 \implies \lambda = \frac{70}{64} = \frac{35}{32} \] ### Step 4: Check for intersection To check if the lines intersect, we need to equate the parametric equations and solve for \( t \) and \( s \): 1. \( 1 - 3t = 1 - \frac{3\lambda}{7}s \) 2. \( 2 + \frac{\lambda}{7}t = 5 + s \) 3. \( 3 + 2t = 6 - 5s \) Solving these equations will give us values of \( t \) and \( s \). If we find consistent values for \( t \) and \( s \), the lines intersect. ### Final Answer The value of \( \lambda \) is \( \frac{35}{32} \).
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If the lines (1 -x )/(3) = ( 7y - 14)/(2 lamda) = (z - 3)/(2) "and" (7 - 7x)/(3lamda) = (y - 5)/(1) = ( 6 - z ) /(5) are at right angle, then the value of lamda is

Fiind m, if the lines (1-x)/(3)= ( 7y-14)/(2m ) = (z-3) /(2) and ( 7-7x)/(3m) = (y-5)/(1) = (6-z)/(5) are at right angles.

(i) Find the value of 'p' so that the lines : l_(1) : (1 - x)/(3) = (7y -14)/(2p) = (z - 3)/(2) and l_(2) : (7 -7x)/(3p) = (y - 5)/(1) = (6 - z)/(5) are at right angles. Also, find the equations of the line passing through (3,2, -4) and parallel to line l_(1) . (ii) Find 'k' so that the lines : (x - 3)/(2) = (y + 1)/(3 ) = (z - 2)/(2k) and (x + 2)/(1) = (4 -y)/(k) = (z + 5)/(1) are perpendicular to each other.

Find the values of lambda if the following of lines perpendicular : (1-x)/(3) = (7y-14)/(3lambda)=(z+1)/(2) and (7-7x)/(3lambda) = y/1 = (1-z)/(5)

Find the value of so that the lines l1: (1-x)/3 = (7y-14)/(2lambda) =(z-3)/2 and l2: (7-7x)/(3lambda) = (y-5)/1 = (6-z)/5 are at right angle. Also find the equation of a line passing through the point (3,2,-4) and parallel to l1.

Find the values p so that line (1-x)/(3)=(7y-14)/(2p)=(z-3)/(2) and (7-7x)/(3p)=(y-5)/(1)=(6-z)/(5) are at right angles.

Find the value of so that the lines (-(x-1))/(3)=(7(y-2))/(2lamda)=(z-3)/(2)and(-7(x-1))/(3lamda)=(y-5)/(1)=(-(z-6))/(5) are perpendicular to each other.

Find the values of p so that the lines (1-x)/(3)=(7y-14)/(2p)=(z-3)/(2)(7-7x)/(3p)=(y-5)/(1)=(6-z)/(5) are at right angles.

If the lines (x-1)/(-3) =(y-2)/(2lambda) =(z-3)/(2) " and " (x-1)/(3lambda) =(y-1)/(1)=(6-z)/(5) are perpendicular to each other then find the value of lambda

Show that the lines : (x + 1)/(3) = (y + 3)/(5) = (z + 5)/(7) and " " (x -2)/(1) = (y - 4)/(3) = (z -6)/(5) intersect each other. Also, find the their point of intersection.

MODERN PUBLICATION-THREE DIMENSIONAL GEOMETRY -EXAMPLE
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  2. Find the direction-cosines of the line: (x-1)/(2) = -y = (z + 1)/(2)...

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  3. Find the vector of the line joining (1,2,3) and (-3, 4,3) and show tha...

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  4. Find the vector equation of the line through (4,3, -1) and parallel to...

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  5. Find the angle between the following pair of lines : vec(r) = hati +...

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  6. Find the angle between the following pair of lines (x-2)/(2) = (y - ...

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  7. Find the points on the line (x+2)/3=(y+1)/2=(z-3)/2\ at a distance...

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  8. Find the equations of the line passing through the point (-1,3,-...

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  9. If hat(i) + hatj + hatk, 2 hati + 5 hatj , 3 hati + 2 hatj - 3 hatk an...

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  10. Find the value of 'lambda' so the lines: (1-x)/(3) = (7y -14)/(lamb...

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  11. Find the length of the perpendicular from point (3,4,5) on the line (x...

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  12. Find the coordinates of the foot of perpendicular drawn from the point...

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  13. Find the vector equation of the line parallel to the line : (x -1)/(...

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  14. Find the equations of the perpendicular drawn from the point P(2,4,-1)...

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  15. Find the image of the point (1,6,3) in the line x/1=(y-1)/2=(z-2)/3 . ...

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