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Find the point of intersection of the li...

Find the point of intersection of the line :
`vec(r) = (hat(i) + 2 hat(j) + 3 hat(k) ) + lambda (2 hat(i) + hat(j) + 2 hat(k))` and the plane `vec(r). (2 hat(i) - 6 hat(j) + 3 hat(k) ) ` + 5 = 0.

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To find the point of intersection of the given line and plane, we can follow these steps: ### Step 1: Write the equation of the line in parametric form The equation of the line is given as: \[ \vec{r} = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda(2\hat{i} + \hat{j} + 2\hat{k}) \] From this, we can extract the parametric equations for \(x\), \(y\), and \(z\): - \(x = 1 + 2\lambda\) - \(y = 2 + \lambda\) - \(z = 3 + 2\lambda\) ### Step 2: Write the equation of the plane in Cartesian form The equation of the plane is given as: \[ \vec{r} \cdot (2\hat{i} - 6\hat{j} + 3\hat{k}) + 5 = 0 \] This can be expanded to: \[ 2x - 6y + 3z + 5 = 0 \] ### Step 3: Substitute the parametric equations into the plane's equation Now, we substitute the values of \(x\), \(y\), and \(z\) from the line's equations into the plane's equation: \[ 2(1 + 2\lambda) - 6(2 + \lambda) + 3(3 + 2\lambda) + 5 = 0 \] ### Step 4: Simplify the equation Expanding this gives: \[ 2 + 4\lambda - 12 - 6\lambda + 9 + 6\lambda + 5 = 0 \] Combining like terms: \[ (2 - 12 + 9 + 5) + (4\lambda - 6\lambda + 6\lambda) = 0 \] This simplifies to: \[ 4 = 0 \] This means that the terms involving \(\lambda\) cancel out, and we are left with a constant. ### Step 5: Solve for \(\lambda\) Since the equation simplifies to \(4 = 0\), it indicates that there is no specific \(\lambda\) that satisfies this equation, meaning the line lies entirely in the plane. ### Step 6: Find the intersection point To find a specific point on the line, we can choose any value for \(\lambda\). Let's choose \(\lambda = 0\): - \(x = 1 + 2(0) = 1\) - \(y = 2 + (0) = 2\) - \(z = 3 + 2(0) = 3\) Thus, one point on the line is \((1, 2, 3)\). ### Step 7: Conclusion Since the line lies in the plane, every point on the line is an intersection point. The specific point we calculated is: \[ \text{Point of intersection: } (1, 2, 3) \]
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vec(r )=(-4hat(i)+4hat(j) +hat(k)) + lambda (hat(i) +hat(j) -hat(k)) vec(r)=(-3hat(i) -8hat(j) -3hat(k)) + mu (2hat(i) +3hat(j) +3hat(k))