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Express the following equation of the li...

Express the following equation of the lines into vector form :
`(x - 3)/(3) = (y - 8)/(-1) = (z - 3)/(1)`
and `(x + 3)/(-3) = (y + 7)/(2) = (z - 6)/(4)`

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To express the given equations of the lines in vector form, we will follow these steps: ### Step 1: Identify the components of the first line The first line is given by the equation: \[ \frac{x - 3}{3} = \frac{y - 8}{-1} = \frac{z - 3}{1} \] From this equation, we can identify the following: - The point through which the line passes (A, B, C) is (3, 8, 3). - The direction ratios (L, M, N) are (3, -1, 1). ### Step 2: Write the vector form of the first line Using the standard vector form of a line: \[ \vec{r} = \vec{a} + \lambda \vec{d} \] where \(\vec{a}\) is the position vector of the point (3, 8, 3) and \(\vec{d}\) is the direction vector (3, -1, 1), we can write: \[ \vec{r_1} = (3\hat{i} + 8\hat{j} + 3\hat{k}) + \lambda (3\hat{i} - \hat{j} + \hat{k}) \] This simplifies to: \[ \vec{r_1} = (3 + 3\lambda)\hat{i} + (8 - \lambda)\hat{j} + (3 + \lambda)\hat{k} \] ### Step 3: Identify the components of the second line The second line is given by the equation: \[ \frac{x + 3}{-3} = \frac{y + 7}{2} = \frac{z - 6}{4} \] From this equation, we can identify: - The point through which the line passes (A, B, C) is (-3, -7, 6). - The direction ratios (L, M, N) are (-3, 2, 4). ### Step 4: Write the vector form of the second line Using the same vector form: \[ \vec{r} = \vec{a} + \mu \vec{d} \] where \(\vec{a}\) is the position vector of the point (-3, -7, 6) and \(\vec{d}\) is the direction vector (-3, 2, 4), we can write: \[ \vec{r_2} = (-3\hat{i} - 7\hat{j} + 6\hat{k}) + \mu (-3\hat{i} + 2\hat{j} + 4\hat{k}) \] This simplifies to: \[ \vec{r_2} = (-3 - 3\mu)\hat{i} + (-7 + 2\mu)\hat{j} + (6 + 4\mu)\hat{k} \] ### Final Answer The vector forms of the lines are: 1. For the first line: \[ \vec{r_1} = (3 + 3\lambda)\hat{i} + (8 - \lambda)\hat{j} + (3 + \lambda)\hat{k} \] 2. For the second line: \[ \vec{r_2} = (-3 - 3\mu)\hat{i} + (-7 + 2\mu)\hat{j} + (6 + 4\mu)\hat{k} \]
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The shortest distance between line (x-3)/(3)=(y-8)/(-1)=(z-3)/(1) and (x+3)/(-3)=(y+7)/(2)=(z-6)/(4) is

(i) Find the equations of the straight line passing through the point (2,3,-1) and is perpendicular to the lines : ( x-2)/(2) = (y + 1)/(1) = (z - 3)/(-3) and (x - 3)/(1) = (y + 2)/(1) = (z - 1)/(1) . (ii) Find the equation of the line which intersects the lines : (x + 2)/(1) = (y - 3)/(2) = (z + 1)/(4) and (x - 1)/(2) = (y - 2)/(3) = (z - 3)/(4) Perpendicular and passes through the point (1,1,1) .

(i) Find the vector and cartesian equation of the line passing through the point (1,2,-4) and perpendicular to the two lines : (x - 8)/(3) = (y + 19)/(-16) = (z - 10)/(7) and (x - 15)/(3) = (y - 19)/(8) = (z - 5)/(-5) . (ii) Find the vector and cartesian equations of the line passing through the point (2,1,3) and perpendicular to the lines : (x -1)/(1) = (y -2)/(2) = (z - 3)/(3) and (x)/(-3) = (y)/(2) = (z)/(5) .

Write the line 2x=3y =4z in vector form

The cartesian equations of line is : (x - 1)/(2) = (y - 2)/(3) = (z -3)/(4) . Write the vector equation.

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

Image of line (x - 2)/3 = (y - 1)/1 = (z - 1)/(-4) in the plane x + y + z = 7 is

Shortest distance between the lines (x-3)/1 = (y-8)/4 = (z-3)/22 and (x+3)/1 = (y+7)/1 = (z-6)/7 is

The cartesian equation of a line is (x - 6) /(2) = ( y + 4)/(7) = (z -5)/(3) , find its vector equation .

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MODERN PUBLICATION-THREE DIMENSIONAL GEOMETRY -EXERCISE 11 (B) (SHORT ANSWER TYPE QUESTIONS )
  1. Show that the three lines with direction cosines (12)/(13),(-3)/(13),...

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  2. Express the following equation of the lines into vector form : (x -...

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  3. Find the cartesian as well as the vector equation of the line passing ...

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  4. (A) The cartesian equations of a line are : (i) (x - 5)/(3) = (y + ...

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  5. (A) find the equation of a line parallel to x-axis and passing through...

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  6. (A ) Find the vector and cartesian equations of the line through the p...

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  7. Find the equation of the line in vector and in cartesian form that ...

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  8. Find the vector equation of the line passing thought the points (-1,\ ...

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  9. Find the vector and cartesian equations of the line that passes throug...

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  10. (A ) Find the equation of a st. line through (-1,2,3) and equally incl...

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  11. Find the angle between the pairs of lines with direction-ratios : (...

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  12. The angle between a line with direction ratios proportional to 2, 2, ...

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  13. Find the angle between the following pairs of lines : (i) vec(r) = ...

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  14. Show that the lines : (i) (x -5)/(7) = (y + 2)/(-5) = (z)/(1) " " a...

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  15. (i) Find the value of 'p' so that the lines : l(1) : (1 - x)/(3) = (...

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  16. Show that the line through the points : (a) (1, -1, 2), (3,4,-2) is ...

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