Home
Class 12
MATHS
Find the distance of the point (1,2,3) f...

Find the distance of the point (1,2,3) from the cor-ordinate axes.

Text Solution

AI Generated Solution

The correct Answer is:
To find the distance of the point \( A(1, 2, 3) \) from the coordinate axes, we will calculate the distance from the x-axis, y-axis, and z-axis separately. ### Step 1: Distance from the x-axis The coordinates on the x-axis can be represented as \( (x, 0, 0) \). For our point \( A(1, 2, 3) \), we can consider the point on the x-axis that corresponds to the x-coordinate of point A, which is \( (1, 0, 0) \). Using the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \] where \( (x_1, y_1, z_1) = (1, 2, 3) \) and \( (x_2, y_2, z_2) = (1, 0, 0) \). Substituting the values: \[ d = \sqrt{(1 - 1)^2 + (2 - 0)^2 + (3 - 0)^2} \] \[ = \sqrt{0^2 + 2^2 + 3^2} \] \[ = \sqrt{0 + 4 + 9} \] \[ = \sqrt{13} \] ### Step 2: Distance from the y-axis The coordinates on the y-axis can be represented as \( (0, y, 0) \). For our point \( A(1, 2, 3) \), we can consider the point on the y-axis that corresponds to the y-coordinate of point A, which is \( (0, 2, 0) \). Using the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \] where \( (x_1, y_1, z_1) = (1, 2, 3) \) and \( (x_2, y_2, z_2) = (0, 2, 0) \). Substituting the values: \[ d = \sqrt{(0 - 1)^2 + (2 - 2)^2 + (0 - 3)^2} \] \[ = \sqrt{(-1)^2 + 0^2 + (-3)^2} \] \[ = \sqrt{1 + 0 + 9} \] \[ = \sqrt{10} \] ### Step 3: Distance from the z-axis The coordinates on the z-axis can be represented as \( (0, 0, z) \). For our point \( A(1, 2, 3) \), we can consider the point on the z-axis that corresponds to the z-coordinate of point A, which is \( (0, 0, 3) \). Using the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \] where \( (x_1, y_1, z_1) = (1, 2, 3) \) and \( (x_2, y_2, z_2) = (0, 0, 3) \). Substituting the values: \[ d = \sqrt{(0 - 1)^2 + (0 - 2)^2 + (3 - 3)^2} \] \[ = \sqrt{(-1)^2 + (-2)^2 + 0^2} \] \[ = \sqrt{1 + 4 + 0} \] \[ = \sqrt{5} \] ### Summary of Distances - Distance from the x-axis: \( \sqrt{13} \) - Distance from the y-axis: \( \sqrt{10} \) - Distance from the z-axis: \( \sqrt{5} \)
Promotional Banner

Topper's Solved these Questions

  • THREE DIMENSIONAL GEOMETRY

    MODERN PUBLICATION|Exercise EXERCISE 11 (C) (LONG ANSWER TYPE QUESTIONS(II) )|8 Videos
  • THREE DIMENSIONAL GEOMETRY

    MODERN PUBLICATION|Exercise EXERCISE 11 (D) (LONG ANSWER TYPE QUESTIONS(I) )|12 Videos
  • THREE DIMENSIONAL GEOMETRY

    MODERN PUBLICATION|Exercise EXERCISE 11 (B) (LONG ANSWER TYPE QUESTIONS (II) )|2 Videos
  • RELATIONS AND FUNCTIONS

    MODERN PUBLICATION|Exercise CHAPTER TEST (1)|12 Videos
  • VECTOR ALGEBRA

    MODERN PUBLICATION|Exercise CHAPTER TEST 10|12 Videos

Similar Questions

Explore conceptually related problems

Find the distances of the point P(-4,3,5) from the coordinate axes.

Find the distances of the point P(2, 3, 2) from the coordinate planes.

Find the distance of the point (1,-2,3) from the line joining the points (-1,2,5) and (2,3,4).

Find the perpendicualr distances of the point P(a,b,c) form the co - ordinate axes

Find the distance of the point (-2, 3, -5) from the line (x+2)/1=(y-3)/2=z/3.

Find the distance of the point (4, 2) from the line joining the points (4, 1) and (2,3).

Find the distance of the point (0,-1) from the line joining the points (1,3) and (-2,6)

Find the projections (feet of the perpendiculars) of the point(1,-2,4) on the Co-ordinate axes

If the sum of the squares of the distance of a point from the three coordinate axes is 36, then find its distance from the origin.