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Find the equation of the plane containin...

Find the equation of the plane containing the line: `(x - 1)/(3) =(y + 2)/(1) = (z - 3)/(2) ` and perpendicular to the plane 2 x - y + 2z - 3 = 0.

Text Solution

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The correct Answer is:
4x -2y - 5z + 7 = 0.
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Find the equation of the plane containing the line. : (x -1)/(2) = (y -2)/(-1) = (z - 3)/(4) and perpendicular to the plane x + 2y + z - 2 = 0 .

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Knowledge Check

  • Equation of the plane containing the line (x+2)/5 = (y-3)/-1 = (z+1)/1 , and perpendicular to the plane barr.(i+j-k)=-3 is

    A
    y+z=2
    B
    y+z+2=0
    C
    x+y=3
    D
    x-y+3=0

  • Equation of plane which contains the line (x-1)/(1)=(y-2)/(3)=(z-3)/(2) and which is perpendicular to the plane 2x+7y+5z=2, is

    A
    `x+y+z=6`
    B
    `-x+y+z=2`
    C
    `2x-y+z=3`
    D
    `x-y+z=2`

  • Equation of the plane E which contains the line L : x = (y-3)/2 = (z-5)/3 , and is perpendicular to the plane , E_(1): 2x + 7y - 3z = 1 is

    A
    `9x-3y-z =14`
    B
    `9x-3y+z=14`
    C
    `9x-3y-z+14=0`
    D
    `9x+3y+z=14`

    • Similar Questions

    Explore conceptually related problems

    Find the equation of plane containing the line (x-2)/(4)=(y-1)/(3)=(z+1)/(-2) aond perpendicular to the plane 2x-y+2z=11

    Find the equation of the plane passing through the straight line (x-1)/(2)=(y+2)/(-3)=(z)/(5) and perpendicular to the plane x-y+z+2=0

    The equation of the plane which contains the line x=(y-3)/2=(z-5)/3 , and which is perpendicular to the plane 2x+7y+3z=1 is …........

    Equation of the plane containing the straight line (x)/(2)=(y)/(3)=(z)/(4) and perpendicular to the plane containing the straight lines (x)/(2)=(y)/(4)=(z)/(2) and (x)/(4)=(y)/(2)=(z)/(3) is

    The equation of the plane containing the lines (x-1)/2=(y+1)/-1=z/3 and x/2(y-2)/-1=(z+1)/3 is

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