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Write the sum of intercepts cut off by t...

Write the sum of intercepts cut off by the plane `vecr(2hati+hatj-hatk)-5=0` on the three axis

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The correct Answer is:
`5/2`
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The intercepts made by the plane vecr.(2hati-3hatj+4hatk)=12 are

Find the equation of the plane through the point hati+4hatj-2hatk and perpendicular to the line of intersection of the planes vecr.(hati+hatj+hatk)=10 and vecr.(2hati-hatj+3hatk)=18.

The plane through the point (-1,-1,-1) nd contasining the line of intersection of the planes vecr.(hati+3hatj-hatk)=0 ,vecr.(hati+2hatk)=0 is (A) vecr.(hati+2hatj-3hatk)=0 (B) vecr.(hati+4hatj+hatk)=0 (C) vecr.(hati+5hatj-5hatk)=0 (D) vecr.(hati+hatj+3hatk)=0

Show that the line of intersection of the planes vecr*(hati+2hatj+3hatk)=0 and vecr*(3hati+2hatj+hatk)=0 is equally inclined to hati and hatk . Also find the angleit makes with hatj .

Prove that the equaton of a plane through point (2,-4,5) and the line o lintersection of the planes vecr.(2hati+3hatj-hatk) = 1 and vecr.(3hati+hatj-2hatk) = 2 is vecr.(2hati+8hatj+7hatk) = 7 .

Find the equation of the plane which contains the line of intersection of the planes vecr.(hati+2hatj+3hatk)-4=0, vecr.(2hati+hatj-hatk)+5=0 and which is perpendicular to the plane vecr.(5hati+3hatj-6hatk)+8=0

Find the equation of the plane which is perpendicualr to the plane vecr(5hati+2hatj+6hatk)+8=0 and which is containg the line of intersection of the planes vecr(hati+2hatj+3hatk)=4 and vecr(2hati+hatj-hatk)+5=0

Find the equation of the plane passing through the line of intersection of the planes vecr.(hati+hatj+hatk)=1 and vecr.(2hati+3hatj-hatk)+4=0 and parallel to x-axis.

The line of intersection of the planes vecr . (3 hati - hatj + hatk) =1 and vecr. (hati+ 4 hatj -2 hatk)=2 is:

Find the equation of the plane through the line of intersection of the planes vecr.(2hati-3hatj+4hatk)=1 and vecr.(hati-hatj)+4=0 and perpendicular to the plane vecr.(2hati-hatj+hatk)+8=0 .