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Find the cartesian equation of the line...

Find the cartesian equation of the line which passes through the point `(-2,4,-5)` and parallel and line are `(3,5,6)`. So, the equation of line is,
`(x-(-2))/(3) = (y-4)/(5) = (z-(-5))/(6)`.

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The correct Answer is:
which is the reqd. cartesian equation of the line .
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MODERN PUBLICATION-THREE DIMENSIONAL GEOMETRY -NCERT-FILE (EXERCISE 11.2)
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  2. Show that the line through the points (1,-1,2) and (3,4-2) is perpe...

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  3. Show that the line through the points (4, 7, 8), (2, 3, 4)is parallel...

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  4. The equation of a line which passes through the point ( 1, 2...

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  5. Find the equation of the line in vector and in cartesian form that ...

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  6. Find the cartesian equation of the line which passes through the poin...

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  7. The vector equationm of the line (x-5)/(3)=(y+4)/(7)=(z-6)/(2) is

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  8. Find the vector and Cartesiasn equation of the line that passes throug...

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  9. Find the vector and the cartesian equations of the line that passes th...

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  10. Find the angle between the following pairs of lines : (i)vec(r) = 2 ...

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  11. Find the angle between the following pair of lines , (i) (x - 2)/(2)...

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  12. Find the values p so that line (1-x)/3=(7y-14)/(2p)=(z-3)/2a n d(7-7x)...

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  13. Show that the lines (x+5)/(7) = (y +2)/(-5) = (z)/(1) and (x)/(1) = (y...

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  14. Find the shortest distance betwee the lines : vec(r) = (hati + 2 hat...

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  15. Find the shortest distance between the lines ( x + 1 ...

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  16. Find the shortest distance between the lines whose vector equations ar...

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  17. Find the shortest distance between the following lines whose vector...

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