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The corner points of the feasible region...

The corner points of the feasible region determined by the following system of linear inequalities:
`2x+yge10, x+3yle15,x,yge0` are `(0,0),(5,0),(3,4)` and `(0,5)`. Let `Z=px+qy`, where `p,qge0`. Condition on `p` and `q` so that the maximum of `Z` occurs at both `(3,4)` and `(0,5)` is:

A

p = q

B

p = 2q

C

p = 3q

D

q = 3p

Text Solution

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The correct Answer is:
D
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