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3 defective bulbs are mixed up with 7 go...

3 defective bulbs are mixed up with 7 good 3 bulbs are drawn at random. Find the probability distribution of defective bulbs.

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The correct Answer is:
`P(0)=(7)/(24),P(1)=(21)/(40),P(2)=(7)/(40),P(3)=(1)/(120)`.
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