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A discrete random variable 'X' has mean ...

A discrete random variable 'X' has mean equal to 3 and variance equal to 2. Assuming that the underlying distribution of 'X' is binomial, find the distribution and hence obtain :
(i) P(X = 0)
(ii) Draw a histogram for the distribution.

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To solve the problem, we need to find the parameters of the binomial distribution given the mean and variance of the random variable \(X\). ### Step 1: Identify the Mean and Variance Formulas In a binomial distribution, the mean (\(\mu\)) and variance (\(\sigma^2\)) are given by: - Mean: \(\mu = np\) - Variance: \(\sigma^2 = npq\) Where: - \(n\) = number of trials - \(p\) = probability of success - \(q\) = probability of failure (where \(q = 1 - p\)) ### Step 2: Set Up the Equations From the problem, we know: - Mean (\(\mu\)) = 3 - Variance (\(\sigma^2\)) = 2 This gives us two equations: 1. \(np = 3\) (1) 2. \(npq = 2\) (2) ### Step 3: Substitute \(q\) in Terms of \(p\) Since \(q = 1 - p\), we can substitute \(q\) in equation (2): \[ np(1 - p) = 2 \] Substituting \(np = 3\) from equation (1): \[ 3(1 - p) = 2 \] ### Step 4: Solve for \(p\) Now, we can solve for \(p\): \[ 3 - 3p = 2 \\ 3p = 1 \\ p = \frac{1}{3} \] ### Step 5: Find \(q\) Now that we have \(p\), we can find \(q\): \[ q = 1 - p = 1 - \frac{1}{3} = \frac{2}{3} \] ### Step 6: Find \(n\) Now, we can substitute \(p\) back into equation (1) to find \(n\): \[ n \cdot \frac{1}{3} = 3 \\ n = 3 \cdot 3 = 9 \] ### Step 7: Summary of Parameters We have found: - \(n = 9\) - \(p = \frac{1}{3}\) - \(q = \frac{2}{3}\) Thus, the binomial distribution is \(X \sim B(9, \frac{1}{3})\). ### Step 8: Calculate \(P(X = 0)\) Using the binomial probability formula: \[ P(X = r) = \binom{n}{r} p^r q^{n-r} \] For \(X = 0\): \[ P(X = 0) = \binom{9}{0} \left(\frac{1}{3}\right)^0 \left(\frac{2}{3}\right)^{9} \\ = 1 \cdot 1 \cdot \left(\frac{2}{3}\right)^{9} \\ = \left(\frac{2}{3}\right)^{9} \] Calculating \(\left(\frac{2}{3}\right)^{9}\): \[ = \frac{2^9}{3^9} = \frac{512}{19683} \] ### Step 9: Draw a Histogram To draw a histogram for the distribution, we would plot the probabilities \(P(X = r)\) for \(r = 0, 1, 2, \ldots, 9\). 1. Calculate \(P(X = r)\) for \(r = 0, 1, 2, \ldots, 9\) using the binomial formula. 2. Use a graphing tool or software to plot the values.
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