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If P(A)=(1)/(2) and P(B)=0, then P(A//B)...

If `P(A)=(1)/(2)` and `P(B)=0`, then `P(A//B)` is equal to :

A

0

B

`(1)/(2)`

C

not defined

D

1

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find \( P(A|B) \), which is the conditional probability of event A given event B. The formula for conditional probability is: \[ P(A|B) = \frac{P(A \cap B)}{P(B)} \] ### Step 1: Identify the given probabilities From the problem, we have: - \( P(A) = \frac{1}{2} \) - \( P(B) = 0 \) ### Step 2: Substitute the values into the conditional probability formula We can substitute the values we have into the conditional probability formula: \[ P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{P(A \cap B)}{0} \] ### Step 3: Analyze the denominator Since \( P(B) = 0 \), the denominator of our fraction becomes zero. In probability theory, division by zero is undefined. ### Conclusion Thus, \( P(A|B) \) is not defined because we cannot divide by zero. ### Final Answer \[ P(A|B) \text{ is not defined.} \] ---
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