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If A and B are two independent events su...

If A and B are two independent events such that `P(A)=(1)/(2),P(A uu B)=(3)/(5)` and `P(B)=p`, then p = _________.

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To solve the problem, we need to find the probability \( P(B) = p \) given the probabilities of events A and B and their union. ### Step-by-Step Solution: 1. **Identify the Given Values:** - \( P(A) = \frac{1}{2} \) - \( P(A \cup B) = \frac{3}{5} \) - \( P(B) = p \) 2. **Use the Formula for the Union of Two Events:** The formula for the probability of the union of two independent events A and B is given by: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] Since A and B are independent, we have: \[ P(A \cap B) = P(A) \cdot P(B) = P(A) \cdot p \] 3. **Substitute the Known Values into the Formula:** Substitute \( P(A) \) and \( P(A \cup B) \) into the union formula: \[ \frac{3}{5} = \frac{1}{2} + p - \left(\frac{1}{2} \cdot p\right) \] 4. **Simplify the Equation:** Rearranging the equation gives: \[ \frac{3}{5} = \frac{1}{2} + p - \frac{1}{2}p \] Combine like terms: \[ \frac{3}{5} = \frac{1}{2} + \left(1 - \frac{1}{2}\right)p \] This simplifies to: \[ \frac{3}{5} = \frac{1}{2} + \frac{1}{2}p \] 5. **Isolate \( p \):** To isolate \( p \), first subtract \( \frac{1}{2} \) from both sides: \[ \frac{3}{5} - \frac{1}{2} = \frac{1}{2}p \] To perform the subtraction, find a common denominator (which is 10): \[ \frac{3}{5} = \frac{6}{10}, \quad \frac{1}{2} = \frac{5}{10} \] Thus: \[ \frac{6}{10} - \frac{5}{10} = \frac{1}{10} \] So we have: \[ \frac{1}{10} = \frac{1}{2}p \] 6. **Solve for \( p \):** Multiply both sides by 2 to solve for \( p \): \[ p = 2 \cdot \frac{1}{10} = \frac{2}{10} = \frac{1}{5} \] ### Final Answer: \[ p = \frac{1}{5} \]
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