Determine P (E|F) in : A die is thrown three times, E : 4 appears on the third toss, F: 6 and 5 appears respectively on first two tosses

A die is thrown three xx.Find P((A)/(B)) and P((B)/(A)), if A=4 appears on the third toss,B=6 and 5 appear respectively on first two tosses.

A die is thrown three xx,find the probability that 4 appears on the third toss if it is given that 6 and 5 appear respectively on first two tosses.

Determine P" "(E|F) in : A coin is tossed three times, where (i) E : Head on third toss, F : heads on first two tosses (ii) E : at least two heads, F : at most two heads (iii) E : at most two tails, F : at least one tail

One dice is thrown three times and the number 4 appears in first throw The probability that the sum of thrown numbers is 15 is

One dice is thrown three times and the number 4 appears in first throw. The probability that the sum of thrown numbers is 15 is

Determine P(E|F) in : Two coins are tossed once,where (i) E: tail appears on one cossed once,where (i) E: tail (ii) E: no tail appears,F: no head appears

(a) A coin is tossed three times. (i) E : heads on third toss , F : heads on first two tosses (ii) E : at least two heads, F : at most two heads (iii) E : at most two tails , F : at least one tail. Find the probability in all cases.

A die is thrown 560 times. The number 6 appears on the upper face 72 times. A die is thrown at random. What is the probability of getting 6.

A coin is tossed three xx.Find P(E/F) in each of the following: (i)E= Head on the third toss,F= Heads on first two tosses (ii) E= At least two heads,F= At most two heads (iii) E= At most two tails,F= At least one tail

Assertion : A die is thrown. Let E be the event that number appears on the upper face is less than 1, then P( E) = 1/6 Reason : Probability of impossible event is 0.