A man takes a step forward with probability 0.4 and backward with probability 0.6. Find the probability that at the end of 5 steps, he is one step away from the starting point.

A man takes a step forward with probability 0.4 and backward with probability 0.6 . The probability that at the end of eleven steps he is just one step away from the starting point, is

A man takes a step forward with probability 0.4 & backward with probability 0.6. Probability that at end of eleven stops he is one step away from starting point is (i).^11C_6(0.24)^6 (ii) .^11C_6(0.4)^6(0.6)^5 (iii) .^11C_5(0.4)^5(0.6)^5 (iv) N.O.T

I take a step forward with probability 0.45 and back with a probability 0.55. What is the probability that after 13 steps I am 3 steps away from the starting point?

A man takes a forward step with probability (.8) and backward step with probability (.2). What is the probability that at the end of 9 steps he is exactly three steps away from starting points ?

A man takes a step forward with probability 0.7 and backward with probability 0.3. If the man takes 12 steps, and let the probability that he is just one step away from his initial position be p, then 13.23 - 15p is equal to ____