Out of (2n+1) tickets consecutively numbered, three are drawn at random. Find the chance that the numbers on them are in AP.

Statement-1: Out of 21 tickets with number 1 to 21, 3 tickets are drawn at random, the chance that the numbers on them are in AP is (10)/(133) . Statement-2: Out of (2n+1) tickets consecutively numbered three are drawn at ranodm, the chance that the number on them are in AP is (4n-10)/ (4n^(2)-1) .

Statement 1: Our of 5tickets consecutively numbered,three are drawn at random.The chance that the numbers on them are in A.P.is 2/15. Statement 2: Out of 2n+1 tickets consecutively numbed,three are drawn at random,the chance that the numbers on them are in A.P.is 3n/(4n^(2)-1) .

Out of 15 tokens consecutively numbered from 1 to 15, 3 tokens are drawn at random. The probability that the numbers on them in AP is

Out of 2n tickets numbered 1,2,......,2n three are chosen at random.The probability that the numbers on them are in A.P.is

A bag contains 20 tickets numbered 1 to 20. Two tickets are drawn at random. Find the probability that both the numbers on the ticket are prime.

A bag contains tickets numbered from 10 to 50 . One ticket is drawn at random . Find the probability that the number on the card is (i) prime (ii) a perfect square .

A box contains 36 tickets numbered from 1 to 36. One ticket is drawn at random. Find the probability that the number on the ticket is either divisible by 3 or a perfect square.

From 4m+1 tickets numbered as 1,2 ,….4m+1…. Three tickets are chosen at random. Find out the probability that the numbers are in A.P. with even common difference.

There are 12 tickets numbered 1 to 12. A ticket is drawn at random. Find the probability that the number on this ticket is either a multiple of 3 or 4.