Let P= {(x,y) : x^(2)+y^(2)=1, x,y in R}...

Let `P= {(x,y) : x^(2)+y^(2)=1, x,y in R}`. Then P is :

A

reflexive

B

symmetric

C

transitive

D

anti-symmetric

Verified by Experts

The correct Answer is:

B

RELATIONS
MODERN PUBLICATION|Exercise MCQ LEVEL-II|21 Videos
RELATIONS
MODERN PUBLICATION|Exercise AIEEE/JEE EXAMINATIONS|1 Videos
REAL NUMBERS
MODERN PUBLICATION|Exercise Multiple Choice Questions (Level-II)|8 Videos
SEQUENCES AND SERIES
MODERN PUBLICATION|Exercise Recent competitive Questions|5 Videos

Similar Questions

Explore conceptually related problems

The relation R defined on the set A = { 1, 2, 3, 4} by : R= {( x,y) : |x^(2)-y^(2)| le 10, x,y in A} is given by :

If A ={(x, y) : y = 4/x, x ne 0} and B = {(x,y): x^2 + y^2 = 8, x, y in R} then

If A = {(x, y) : x^2 = y, x, y in R} B = {(x, y) : y = |x|, x, y in R} then

Let A={(x,y): y= e^x , x in R } , B={(x,y): y= e^(-x) , x in R } . Then :

If A = {(x, y) : y^2 = x, x, y in R} , B = {(x, y) : y = |x|, x, y in R} , then

Let A={(x,y : y=e^x , x in R } , B={(x,y): y=x, x in R} . Then :

Let A={1,2,3....14}. Define a relation R from A to A by R={(x,y) : 3x-y=0," where "x, y in A} . Write down its domain, condomain and range.

Let a relation R in the set of natural number be defined by (x,y) in R iff x^(2)-4xy+3y^(2)=0 for all x,y in N . Then the relation R is :

In the set of A = {1, 2, 3, 4, 5} , a relation R is defined by R = (x,y) : x, y in A, x lt y) Then R is

Let A ={ 1,2,3…….14} Define a relation R from A to A by R ={ x,y} : 3x -y =0 where x,y in A } Write down is domain and range