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If (a + ib)^5 +alpha+i beta then (b+ia)...

If `(a + ib)^5 +alpha+i beta` then `(b+ia)^5` is equal to (A) `beta - ialpha` (B) `beta +ialpha` (C) `alpha - ibeta` (D) ` -alpha - i beta`

A

`alpha-ibeta`

B

`beta+ialpha`

C

`beta-ialpha`

D

`-alpha-ibeta`

Text Solution

Verified by Experts

The correct Answer is:
B
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