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If the cube root of unity are 1,omega,om...

If the cube root of unity are `1,omega,omega^(2)`, then the roots of the equation `(x-1)^(3)+8=0` are :

A

`-1,-1,-1`

B

`-1,-1+2omega, -1-2omega^(2)`

C

`-1,1+2omega, 1+2omega^(2)`

D

`-1,1-2omega, 1-2omega^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
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