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If the roots of the equation `(x^(2) -bx)/(ax - c) = (lambda - 1)/(lambda + 1)` are such that `alpha + beta =0 `, then the value of `lambda` is :

A

`(a - b)/(a + b)`

B

c

C

`(1)/(c)`

D

`(a + b)/(a - b)`

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A
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