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2x +sqrt6y=2 touches the hyperbola x^2-2...

`2x +sqrt6y=2` touches the hyperbola `x^2-2y^2=4` , then the point of contact is :

A

`(-2,sqrt6)`

B

`(-5,2sqrt6)`

C

`(1/2,1/sqrt6)`

D

`(4,-sqrt6)`

Text Solution

Verified by Experts

The correct Answer is:
D
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