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The distance of the focus of x^2-y^2=4, ...

The distance of the focus of `x^2-y^2=4`, from the directrix , which in near to it is :

A

`sqrt2`

B

`2sqrt2`

C

`8sqrt2`

D

`4sqrt2`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • The distance of the focus of x^(2) - y^(2) =4 from the directrix which is near to it is :

    A
    `sqrt(2)`
    B
    `2sqrt(2)`
    C
    `8sqrt(2)`
    D
    `4sqrt(2)`

  • The distance of the focua of x^(2)-y^(2)=4 from the directrix which is nearer to it, is

    A
    `7sqrt(2)`
    B
    `4sqrt(2)`
    C
    `sqrt(2)`
    D
    `2sqrt(2)`

  • The distance of the P on the parabola y^(2)=4 x from the focus is 26. Then P=

    A
    (4,4) or (4,-4)
    B
    `(3,2 sqrt(3))` or `(3,-2 sqrt(3))`
    C
    (25,10) or (25,-10)`(mathrm
    D
    (16,8)` or (16,-8)

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