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If A+B+C=(3pi)/(2), then cos2A+cos2B+cos...

If `A+B+C=(3pi)/(2)`, then `cos2A+cos2B+cos2C=`

A

`1-4cosAcosBcosC`

B

`4sinAsinBsinC`

C

`1+2cosAcosBcosC`

D

`1-4sinAsinBsinC`

Text Solution

Verified by Experts

The correct Answer is:
D
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