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The conductivity of 0.001 M acetic is 4...

The conductivity of 0.001 M acetic is ` 4 xx 10^(-5)S//cm.` Calculate the dissociation constant of acetic acid, if molar conductivity at infinite dilution for acetic is 390 S `cm^(2)//mol.`

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Calculating the value of dissociation constant of weak electrolyte: The conductivity of 0.001028 mo L^(-1) acetic acid is 4.95 xx 10^(-5) S cm^(-1) . Calculate its dssociation constatnt if Lambda_(m)^(0) for acetic acid is 390.5 S cm^(2) mol^(-1) . Strategy: We can determine the value of the dissociation constant for week electrolytes once we know the Lambda_(m)^(0) and Lambda_(m) at any given concentration C .

The conductivity of 0.001028M acetic acid is 4.95xx10^(-5)Scm^(-1) . Calculate its dissociation constant if Lambda_(m)^(0) for acetic acid is 390.5Scm^(2)mol^(-1) .

The conductivity of 0.001028 M acetic acid is 4.95xx10^(-5) S cm^(-1) . Calculate dissociation constant if wedge_(m)^(@) for acetic acid is 390.5 S cm^(2) mol ^(-1) .

At 298 K, the specific conductance of 0.1 M acetic acid solution was found to be 0.00163Omega^(-1)cm^(-1) . Calculate the degree of dissociation and dissociation constant of the acid if its molar conductance at infinite dilution is 390.7 Omega^(-1) cm^(2)mol^(-1) .

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