IUPAC name of product formed by reaction of methyl amine with two moles of ethyl chloride

Options

A. N,N-Dimethylethanamine
B. N,N-Diethylmethanamine
C. N-Methyl ethanamine
D. N-Ethyl ,N-methylethanamine

Answer

To determine the IUPAC name of the product formed by the reaction of methyl amine with two moles of ethyl chloride, we can follow these steps:

### Step 1: Identify the Reactants
- The reactants are methyl amine (CH₃NH₂) and ethyl chloride (C₂H₅Cl).

### Step 2: Understand the Reaction
- Methyl amine is a nucleophile due to the lone pair of electrons on the nitrogen atom. Ethyl chloride contains a chlorine atom, which is a good leaving group.
- When methyl amine reacts with ethyl chloride, the nitrogen atom will attack the ethyl group, displacing the chlorine atom.

### Step 3: First Reaction
- The first reaction involves one mole of ethyl chloride reacting with methyl amine:
\[ CH₃NH₂ + C₂H₅Cl \rightarrow CH₃N(C₂H₅)H + HCl \]
- The product formed is N-ethylmethylamine (CH₃N(C₂H₅)H).

### Step 4: Second Reaction
- The product N-ethylmethylamine can further react with another mole of ethyl chloride:
\[ CH₃N(C₂H₅)H + C₂H₅Cl \rightarrow CH₃N(C₂H₅)₂ + HCl \]
- The final product formed is N,N-diethylmethylamine (CH₃N(C₂H₅)₂).

### Step 5: Assign the IUPAC Name
- According to IUPAC nomenclature, the name of the product is derived from the substituents attached to the nitrogen atom and the longest carbon chain.
- The final product is named as N,N-diethylmethylamine.

### Final Answer
The IUPAC name of the product formed by the reaction of methyl amine with two moles of ethyl chloride is **N,N-diethylmethylamine**.

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