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Na(2)S +Na(2)[Fe(CN)(5)NO] to "A" ("Viol...

`Na_(2)S +Na_(2)[Fe(CN)_(5)NO] to "A" ("Violet Color")`
In Complex "A", number of type of ambidentate ligand is/are "a" and number of d-orbital involved in hybridisation is/are "b" The 7a+8 b will be :

Text Solution

Verified by Experts

The correct Answer is:
30
`A-=Na_(4)[Fe(CN)_(5)NOS]`
Ambidentate ligand[a] `=CN^(-),NOS^(-)`
a=2
Hybridisation `implies d^(2)sp^(3) implies b=2`
7a+8b=30
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