Co-ordination number of platinum in `[Pt(NH_(3))_(4)Cl_(2)]^(2+)` ion is :

Options

A. 4
B. 2
C. 8
D. 6

Answer

To determine the coordination number of platinum in the complex ion `[Pt(NH₃)₄Cl₂]²⁺`, we follow these steps:

### Step 1: Identify the central metal atom
The central metal atom in the complex is platinum (Pt).

### Step 2: Identify the ligands
In the given complex, there are two types of ligands:
- Ammonia (NH₃) which is a neutral ligand.
- Chloride (Cl⁻) which is a negatively charged ligand.

### Step 3: Count the number of ligands attached to the central metal atom
- There are 4 ammonia (NH₃) ligands.
- There are 2 chloride (Cl⁻) ligands.

### Step 4: Calculate the coordination number
The coordination number is defined as the total number of ligand donor atoms that are bonded to the central metal atom.
- Each NH₃ ligand donates 1 pair of electrons (1 donor atom).
- Each Cl⁻ ligand also donates 1 pair of electrons (1 donor atom).

Thus, the total number of donor atoms is:
- From NH₃: 4 ligands × 1 donor atom = 4
- From Cl⁻: 2 ligands × 1 donor atom = 2

Adding these together gives:
\[ \text{Total donor atoms} = 4 + 2 = 6 \]

### Conclusion
The coordination number of platinum in the complex `[Pt(NH₃)₄Cl₂]²⁺` is 6.

### Final Answer
The coordination number of platinum in `[Pt(NH₃)₄Cl₂]²⁺` is **6**.

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